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本帖最后由 woaishuijia 于 2011-7-21 05:43 编辑
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1 ? ?, m4 n8 T+ q用VBa做了个简单的小程序,居然提示“无效的过程调用或参数”
( v8 S2 W- @, y% m4 O- m7 W程序:
/ x" s& g7 H% t6 P# e) c+ w( c) k- Public Sub HTT()+ \4 C6 N+ e3 ]5 e* {7 X! t; R: M
- Dim Pt0, PT00 As Variant0 T+ m e# q9 |6 b
- Dim PT1(0 To 2), PT2(0 To 2), PT3(0 To 2) As Double
; U) e0 @7 s- F, w - Dim L0, L1 As Double% p: q6 t' w$ }: o2 u
- Dim i, m, n As Integer
4 _; I2 _% o6 H6 p' j! d' O& m3 t2 \! U - Dim ALine As AcadLine
/ ~. S! C! E* Y/ P0 r5 Z* O - Pt0 = ThisDrawing.Utility.GetPoint(, "基点:")* A @8 e( ^7 `1 S- \1 ~* d/ y, I
- X1 = Pt0(0) r! c+ n/ i3 n4 I
- Y1 = Pt0(1)
: G3 u* ~' O# _9 D5 b - L0 = ThisDrawing.Utility.GetDistance(, "单节筒节宽度:")# c% z+ ]7 e# D+ s' H, ^2 T$ q
- L1 = ThisDrawing.Utility.GetDistance(, "筒节直径:")
+ z5 L7 y# c* V- J% V0 Z) ]% M+ h - PT1(0) = Pt0(0) + L13 s/ P( _, T/ z: W1 d
- PT1(1) = Pt0(1)
+ t" t& _; w0 r; [" } - PT1(2) = Pt0(2)
2 E; c* R# o L' o- u; A5 K5 j - PT2(0) = Pt0(0) + L1
+ W; k1 ?/ R: O! `; P3 P - PT2(1) = Pt0(1) - l2" B6 N8 _; U. p
- PT2(2) = Pt0(2)- @9 g5 O0 A6 X. \1 c
- PT3(0) = Pt0(0)
2 c: n5 m) g1 H8 f) G9 K% x - PT3(1) = Pt0(1) - l2
6 w3 }" j [. b, j4 q6 E! M0 V' ? - PT3(2) = Pt0(2)- L) H! V% o- n; z+ I9 @
5 c7 U# }: U% v' y4 F9 W+ b* O$ X9 J- Set ALine = ThisDrawing.ModelSpace.AddLine(Pt0, PT1), y3 [# Q x, I
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT1, PT2)) K2 S; i/ S! k
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT2, PT3)
5 p2 f# w$ G3 L4 E, ~% c - Set ALine = ThisDrawing.ModelSpace.AddLine(PT3, Pt0)
/ N1 ?- q# a2 t7 X% g; M - ZoomAll
7 p4 k L3 ]& l$ M! z - End Sub
复制代码
, ?( k* t" \& o) G错误提示:7 n1 |4 j% k: k% k6 K+ V" E8 q. z% G
/ U/ a: T8 o, @. _) u" r有知道如何解决的吗? |
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