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UID396100
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在线时间 小时
注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器* M- s% D0 u( N
插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗
' i5 I; Z3 l5 M/ Z- ASub jkx()
' N; [% v" t5 V+ \/ Z# eRem 绘制渐开线,
# K" B# u h9 v# |) _. tDim d As Double '节圆直径9 k! M5 S6 l) q, r: H9 z
Dim r As Double '节圆半径* {: n' M/ n( `; T
Dim A As Double '总展开角度3 N( t& }" u! N, ~; x0 B! M
Dim Ai As Double '展开角度6 |5 m1 u7 w7 g3 ^
Dim Li As Double '展开弧长8 D2 y0 C+ m. k- S
d = 100
: q& y5 M } H7 [2 M! A# yA = 360
' ]* Y8 u9 @! c: }( X6 l% r; {0 b/ Z% sr = d / 2" M8 i) M- F7 x6 y/ O3 l m: M: h
Dim Pnt1(2) As Double {, [* o" C! ]- F
Dim Pnt2(2) As Double2 q- ?# T5 H& {+ v/ F$ t$ F0 N+ U
Dim PntLst() As Double, N As Integer0 Y7 l) V: w6 x+ A& \
ThisDrawing.ModelSpace.AddCircle Pnt1, r
4 g7 g5 l/ a+ e0 Y. w0 G! ]$ KFor Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#& o/ f/ F# u2 ]% A( U/ h
Li = r * Ai9 f( ?% L( d E* c) U
Pnt1(0) = r * Sin(Ai)2 R1 I2 T {$ l+ M% P- q
Pnt1(1) = r * Cos(Ai)' ]* N; i, D4 L! s
Pnt2(0) = Pnt1(0) - Li * Cos(-Ai)3 |" f( k9 ~3 g1 t6 Q. F2 x
Pnt2(1) = Pnt1(1) - Li * Sin(-Ai)% W; _; I; J {
ThisDrawing.ModelSpace.AddLine Pnt1, Pnt2
* z& Z8 K8 {8 z( n# j: |N = N + 1$ B7 T, b! B0 A" Q
ReDim Preserve PntLst(N * 2 - 1); t3 ?' {; D" R* \( @2 x+ ]
PntLst(N * 2 - 2) = Pnt2(0)
. }& G1 `+ o4 F5 _; V* `( r) ^PntLst(N * 2 - 1) = Pnt2(1), | ]3 B$ t3 r$ y [
Next
) R; C2 E0 W- f7 G$ g rIf N > 1 Then
$ {3 `$ H' U* ^5 T$ yThisDrawing.ModelSpace.AddLightWeightPolyline PntLst! d/ p$ A. m5 Y E1 Q
End If
2 E6 H7 w* B( q! T$ z# XEnd Sub |
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