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注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器
# ]2 s; T3 Y. M, N2 ~/ Q 插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗8 J! K M/ q( ?' v2 f
Sub jkx()4 z0 c) b9 U! H. p2 O( X
Rem 绘制渐开线,
) P8 J/ z$ U4 M1 q- e$ q( WDim d As Double '节圆直径+ \, ~' m: N# g( W8 U7 Z
Dim r As Double '节圆半径
2 G( P, d( w. k! Z. M6 fDim A As Double '总展开角度5 `# P' q& V1 v% s( J/ x2 z
Dim Ai As Double '展开角度' _# C! N* C, I
Dim Li As Double '展开弧长
4 B& `* L% A7 Z: V& n; [d = 100
) |: Z" L8 ^3 C4 WA = 360
H) f8 T! `+ ir = d / 2
; ]; @$ A4 T! O H4 @8 x0 P/ aDim Pnt1(2) As Double7 c$ v3 _* X# X! R/ Q1 o3 T/ [
Dim Pnt2(2) As Double6 d, p* }5 W! q) I- Y9 P
Dim PntLst() As Double, N As Integer
/ }) j2 Y J' n" FThisDrawing.ModelSpace.AddCircle Pnt1, r
, R9 h0 R B, R$ e7 U* SFor Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#
; {& V. n# u+ l6 U( ]1 GLi = r * Ai7 I2 u' Y, n+ F. h6 ?$ J8 e( {4 @/ y
Pnt1(0) = r * Sin(Ai)
& ?, C( R: \5 L7 V( q) BPnt1(1) = r * Cos(Ai)* [8 ?/ }$ v+ _- V) Q
Pnt2(0) = Pnt1(0) - Li * Cos(-Ai)
d7 j/ y) l! o6 p0 _Pnt2(1) = Pnt1(1) - Li * Sin(-Ai)
' P# z( N6 Z0 L- [$ aThisDrawing.ModelSpace.AddLine Pnt1, Pnt23 A3 R, p% }, M' K, @! S" w; T8 C+ O- _
N = N + 1
' I5 s! o. S8 P5 i+ P$ @3 n4 BReDim Preserve PntLst(N * 2 - 1)
Z7 U1 }# _# g! A8 T TPntLst(N * 2 - 2) = Pnt2(0)! g% f2 Z! K: a- Z( F, Q
PntLst(N * 2 - 1) = Pnt2(1)
3 J0 V& x. e9 E) W: lNext/ V+ B7 e# C4 A+ _, z$ \- d1 V& O( p
If N > 1 Then
+ r! ^# U* B. f% o: f; d% FThisDrawing.ModelSpace.AddLightWeightPolyline PntLst
! ?! Y- P1 n/ g. K: J- R1 cEnd If
8 K, ^' i* P% [: Z8 [End Sub |
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