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楼主 |
发表于 2016-3-11 15:51:37
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来自： 中国浙江嘉兴
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至于用宏的方法，那里可以找到相关资料？ 之前已分享不少了,若是不能吸收理解,就僅能抄襲無法廣用.
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* `3 w( M: I" E如下參考
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' ******************************************************************************
6 y/ L! U; Z. i' macro recorded on 03/04/16 by scliang( z+ B0 V. ^4 Z- c& e2 |
' ******************************************************************************
' M4 n; u' A nDim swApp As Object! ?; \8 n7 [3 ^9 c; |$ D6 J
Dim Part As Object
. c2 p3 b( a$ ?$ t5 vDim boolstatus As Boolean
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Sub main()1 \ m0 |. A$ t7 }
Set swApp = Application.SldWorks
- k0 r8 Y+ O/ W3 s5 s/ {; ?4 sSet Part = swApp.ActiveDoc0 H, [, k- X* Z- ?
Set myModelView = Part.ActiveView" l# e D3 a8 [$ A: g
Dim myDimension As Object
E) w2 c. O' s1 p" I: j& Spi = Atn(1) * 4% B4 x& L( h$ {9 P* x9 Z/ n
Set myDimension = Part.Parameter("D15@草圖1") '對應控制角度" h7 k2 k* X! Z" E# i; A' a o
For i = 0.1 To 90.1 Step 5
' `" J# j m0 GA = i * pi / 180
, d$ v1 B5 u, p# C; d, SmyDimension.SystemValue = A
" U) l* S5 d% _: e% vboolstatus = Part.EditRebuild3()5 g K$ Q: D" J6 {# _% s0 ?
myModelView.RotateAboutCenter 0, 0. |0 k+ D n: y- c3 f
Next% Q5 p* U5 O" \2 y1 _' j- W
For i = 85.1 To 0.05 Step -5; S0 Y: W, c& M6 B
A = i * pi / 1803 |6 ^8 M* b% x. t+ `. q: s
myDimension.SystemValue = A. c$ ]6 q) T; m
boolstatus = Part.EditRebuild3()
4 v; z7 D, d4 BmyModelView.RotateAboutCenter 0, 0
b, ~7 u. _( R7 |' s1 x7 sNext3 E- X* ~( u* Z' V$ V& l
End Sub
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Macro1.rar
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发表于 2016-3-4 23:27:33
发表于 2016-3-5 07:17:16
