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发表于 2019-12-8 22:50:36
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来自： 中国吉林
以默认MPLFAN为例,搜索 % p6 l2 |% J8 A, p2 F
psgcode #Output the Gcode based on the current plane8 B; x2 o% b0 f9 M
找到代码
8 w, I7 [" J# B g6 u" }% c: {& cpsgcode #Output the Gcode based on the current plane0 e& \* `' g. d9 i; n) l. J
if c_ax_flp,
; h: l# J' Q) c9 u; F0 |% ` [
, Y; T6 J( D* v7 U6 R #Reverse arc direction for c_axis flip
, f! o4 T5 E! D/ G' A2 J2 h if gcode$ = two | gcode$ = three,
& R& k0 j* U/ f0 t+ x& r4 ] [( g) G6 W* q& r
sav_gcode = gcode$4 L+ a+ A3 X" T: v% j: S8 ? K) j g
gcode$ = (5 - gcode$) #G02->G03 or G03->G02; ?4 o0 y* f$ \2 F) u* T0 l1 R
]( o5 K0 F, g$ {) K
]
* D+ N" u' F% d) l( g% s5 q if plane$ = zero, `sgcode
: t5 K% V v$ W/ C. b if plane$ = one, `sgcode1
* M; d) l4 G9 J3 J if plane$ = two, `sgcode2
% V. e' O7 H6 N/ @4 A if c_ax_flp, gcode$ = sav_gcode
, o1 u0 Q- I) d) n) K+ {7 W6 d: T8 U9 h* Z( x$ b4 Y/ x9 i
加点作料改为2 v; C/ g& u6 X: Z
psgcode #Output the Gcode based on the current plane
2 d J4 l) M8 f if c_ax_flp,! P Q% [3 _8 g9 A1 p/ J/ P3 I* `
[ m2 y5 L4 a" t% f4 u7 J
#Reverse arc direction for c_axis flip
" r8 C3 }" u7 _ if gcode$ = two | gcode$ = three,
- g' o% \$ R: p [
9 L5 a8 { W. J sav_gcode = gcode$1 i1 b. f& y' C" }% X
gcode$ = (5 - gcode$) #G02->G03 or G03->G02
8 h/ \4 [5 o" m, {% l ]7 L3 J. Q, Q1 I2 l) N
]6 ?8 ^7 k, d( T
if gcode$ = 2 | gcode$ = 3, result = force(gcode$). |0 `4 \9 [9 T1 ?
if plane$ = zero, `sgcode: ]" E/ j- E' W' P0 F$ ^8 O
if plane$ = one, `sgcode19 ]5 n5 Y* t2 \8 i4 [! N* D
if plane$ = two, `sgcode2, m# `! Z$ \- j3 T% z
if c_ax_flp, gcode$ = sav_gcode
! W' o3 u- [- [ Z/ \; n保存 完事 |
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发表于 2019-12-8 13:42:50