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6 P3 w: e7 M% p2 m5 Q! B: k提示:已知一个圆柱体的顶面温度和侧面、底面温度,求温度分布。
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/ |/ G6 ~4 B' _/ VTitle Temperature Distribution in a Short, Solid Cylinder* {- B7 m3 a! G5 A( K" D5 V! n
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Overview
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' O! e& ?. v, W' H| Reference: | P. J. Schneider, Conduction Heat Transfer, 2nd Printing, Addison-Wesley Publishing Co., Inc., Reading, MA, 1957, pg. 134, fig. 6-7. | | Analysis Type(s): | Thermal Analysis | : `& m) h; E+ D! ~" d0 h% ^- ?
Test Case
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3 D; U0 Y1 V2 W, ~1 J8 jA short, solid cylinder is subjected to the surface temperatures shown. Determine the temperature distribution within the cylinder3 ?9 P3 [, h' O4 B9 G" F
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Figure 96.1 Short, Solid Cylinder Problem Sketch
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) j7 ~- z' F+ X/ h; ]8 ~: T& }# R| Material Properties | | k = 1.0 Btu/hr-ft-°F |
| | Geometric Properties | | r =l= 0.5 ft |
| | Loading | | Ttop = 40°F | | Tbot = Twall = 0°F |
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3 K6 ^) y x' j5 R/ ~Analysis Assumptions and Modeling NotesSince the problem is axisymmetric, the entire cylinder geometry is not required. An angle Θ = 45° is arbitrarily chosen. Postprocessing is used to print temperatures at the centerline in geometric order. A finer mesh density (than required for reasonable results) is used to produce a smooth isosurface plot.9 G* X% M+ b$ [* I4 F
. T& c% V% H! R; T3 tResults Comparison| At Centerline | Target | ANSYS | Ratio | | z = 0.0 ft | T, °F | 0.0 | 0.0 | -- | | z = 0.125 ft | T, °F | 6.8 | 6.8 | 1.007 | | z = 0.25 ft | T, °F | 15.6 | 15.4 | 0.984 | | z = 0.375 ft | T, °F | 26.8 | 26.6 | 0.991 | | z = 0.5 ft | T, °F | 40.0 | 40.0 | 1.00 |
$ L0 F O3 L" ^$ MFigure 96.2 Temperature Isosurface Display with Annotation" A* b: j) ?1 \ I- B
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[ 本帖最后由 tigerdak 于 2007-11-6 12:02 编辑 ] |
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