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本帖最后由 yit02yit02 于 2010-12-10 05:15 编辑
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到台灣三重湯城欣昊((充電))上課五天
# u* V. S- t l" S$ b/ M這次幫我們上課的是陳漢傑老師
9 e3 T, m( v. V% K5 b1 a- |8 @" b7 l我也問了關於G82 P10000 萬分位的問題(一般是千分位)# Z( `' \/ B Z- r
陳老師也幫我解決了這方面的困擾
0 ?' S$ Z, q8 y% R: `首先開啟POST
4 _" c' ] @- ~* n6 J. `找到
H' a7 g+ J1 Y' L# Format statements - n=nonmodal, l=leading, t=trailing, i=inc, d=delta
4 J0 Y2 _! X/ J5 o; N+ [0 O# --------------------------------------------------------------------------
, \* i6 U+ ]9 p: _8 g#Default english/metric position format statements; f! y( E0 t- I' {+ K
fs2 1 0.7 0.6 #Decimal, absolute, 7 place, default for initialize (
1 I, K) C; |/ Q W: {' pfs2 2 0.4 0.3 #Decimal, absolute, 4/3 place- x3 J, x6 `) }! x5 |
fs2 3 0.4 0.3d #Decimal, delta, 4/3 place* m& ^& z9 }3 x) A# Z3 X
#Common format statements5 V1 U- `6 w9 I) Q
fs2 4 1 0 1 0 #Integer, not leading
- \+ |/ q! w- @+ }0 Ufs2 5 2 0 2 0l #Integer, force two leading
5 g7 o% ?- X) n N7 d$ N+ Wfs2 6 3 0 3 0l #Integer, force three leading
/ J- T7 H5 l6 w, O# Mfs2 7 4 0 4 0l #Integer, force four leading: `" L! N$ ^6 T9 B
fs2 8 5 0 5 0l #Integer, force five leading7 j' Q6 s2 G- k& x
fs2 9 0.1 0.1 #Decimal, absolute, 1 place4 |( z0 p. g! T
fs2 10 0.2 0.2 #Decimal, absolute, 2 place
1 @7 [- ^8 `; Qfs2 11 0.3 0.3 #Decimal, absolute, 3 place$ e2 v, z1 W9 C3 x7 ^3 z1 X
fs2 12 0.4 0.4 #Decimal, absolute, 4 place
1 A3 L! J% k7 }fs2 13 0.5 0.5 #Decimal, absolute, 5 place+ K+ p9 R8 p) u- a
fs2 14 0.3 0.3d #Decimal, delta, 3 place; G( F7 |$ D" ?5 `. w- N: \" j8 {
fs2 15 0.2 0.1 #Decimal, absolute, 2/1 place (feedrate)
! l7 n6 X9 K) L: ]( C+ w4 jfs2 16 1 0 1 0n #Integer, forced output- z2 P# R; L1 z* I8 o
fs2 17 1.4 1.3lt #Decimal, absolute, 4/3 trailing' U+ l' V/ w3 F- ^, |- n
fs2 18 0 4 0 4t (增加這一行)) ?5 ]9 R3 }0 k! o
2 @; s" c: ^1 m4 L3 L& m5 W5 ^再找到( d7 |: D) ?+ }% [; @- D+ C: p' G# _
# --------------------------------------------------------------------------) Z: L& R9 L; ?/ p
fmt N 4 n$ #Sequence number
0 H7 n4 y% w* h3 M+ z# Efmt X 2 xabs #X position output6 f: Z5 F6 I/ |
fmt Y 2 yabs #Y position output2 x' n3 E0 ]* P* u+ t6 I+ q; y
fmt Z 2 zabs #Z position output
# T' a) u& i) Z5 rfmt X 3 xinc #X position output: Z1 V8 p3 c+ Q9 j8 T1 k
fmt Y 3 yinc #Y position output
; R3 r- q+ e0 l- A( t' A" S7 t' xfmt Z 3 zinc #Z position output) D! s" x( A4 v9 E# ]
fmt A 11 cabs #C axis position6 W5 {% U/ s% `3 c/ B
fmt A 14 cinc #C axis position
1 |2 x( n4 J u6 P0 ~4 t* Cfmt A 14 cout_i #C axis position
6 y j) O% n* E# \fmt A 4 indx_out #Index position, o2 E: N# n2 c3 J
fmt R 14 rt_cinc #C axis position, G68: `5 J* v" d# C* v
fmt I 3 iout #Arc center description in X5 G" t6 s" G! e3 a& O
fmt J 3 jout #Arc center description in Y: g/ c' {" Y; C
fmt K 3 kout #Arc center description in Z
# G5 O& e2 k* y& [4 q+ F( P [fmt K 2 lead #Helical lead
2 P( Q& r+ b8 Ufmt R 2 arcrad$ #Arc Radius4 w7 l: v/ [% Q2 U* [1 p+ y
fmt F 15 feed #Feedrate
9 s1 H, d( Y7 W! A+ O3 _fmt P 11 dwell$ #Dwell (把P11改P18)& V+ s! u, ^- {% Q* }* s
fmt M 5 cantext$ #Canned text6 u( W3 C/ S$ P! K) q
fmt 4 mr2$ #HSM+ V- ^! G$ B) j% H
程式選G82時暫停時間打1.0' K0 a; a$ _1 x) K! U: ^& C4 I
轉出來就會是G82 P10000, p4 b, ?$ Y( O; k8 ~5 L
真是謝謝)))陳老師))))) |
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发表于 2010-12-10 05:08:54
楼主