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本帖最后由 woaishuijia 于 2011-7-21 05:43 编辑 0 A: O% f; B6 c/ U- ]
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用VBa做了个简单的小程序,居然提示“无效的过程调用或参数”
5 P- K5 A( I: {: j* q. O1 @程序:
; T) T$ a7 W9 A9 S8 G* K3 N; u- Public Sub HTT()/ `; L6 v7 T3 j; N% k
- Dim Pt0, PT00 As Variant
! i( ^) Z) u9 {) j$ R - Dim PT1(0 To 2), PT2(0 To 2), PT3(0 To 2) As Double0 Y- G* Y. v5 @
- Dim L0, L1 As Double
8 V1 F6 O+ S( e. N - Dim i, m, n As Integer c; T$ R9 @% v3 o$ ^9 |, j& ]
- Dim ALine As AcadLine# a# b9 }$ C, C5 s/ _1 d8 Y8 O
- Pt0 = ThisDrawing.Utility.GetPoint(, "基点:")
1 p% _; X1 o- l+ B: T - X1 = Pt0(0)) Y/ Q8 m# o' \1 T6 X9 ?7 ~0 X
- Y1 = Pt0(1)
& {' [/ m7 {3 O8 U% n - L0 = ThisDrawing.Utility.GetDistance(, "单节筒节宽度:")
7 K* l3 ~+ h; \. d$ g9 } - L1 = ThisDrawing.Utility.GetDistance(, "筒节直径:"), r2 L# z, H. B
- PT1(0) = Pt0(0) + L1
; `4 e# J4 ]6 N* v - PT1(1) = Pt0(1)' ^6 v/ T6 O' ~ ]- J# i
- PT1(2) = Pt0(2)
0 a5 T& _9 H' x1 Y+ r8 P - PT2(0) = Pt0(0) + L1
5 ^* f4 \" c6 r - PT2(1) = Pt0(1) - l2 f6 C0 g" T: H9 s
- PT2(2) = Pt0(2)$ |1 j9 @, L7 i3 D' [7 q8 G
- PT3(0) = Pt0(0)% z/ p( t4 c- k) G2 j" V# D
- PT3(1) = Pt0(1) - l24 A* k. w* C) @5 Z9 r7 p
- PT3(2) = Pt0(2)
- I) Y, m& I- @/ y) Z6 j - + h) o* c+ H1 x! v$ q7 J
- Set ALine = ThisDrawing.ModelSpace.AddLine(Pt0, PT1)2 o3 g2 M+ ^ k& F9 p1 Z
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT1, PT2)
8 _( L, [3 W5 _( {: }- L - Set ALine = ThisDrawing.ModelSpace.AddLine(PT2, PT3)
' V0 Q2 e+ T" t$ t0 a/ Y$ w9 b: }2 h - Set ALine = ThisDrawing.ModelSpace.AddLine(PT3, Pt0)
! c) z1 d8 p. J1 ~5 k: O2 L5 f9 B - ZoomAll
2 p" Q' j; e. ^+ W' I; T - End Sub
复制代码 + u1 D& R1 r. u2 F& U
错误提示:# B0 v0 m8 e" I9 k
! a; s# u$ E2 h/ z# ]有知道如何解决的吗? |
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