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& L% r; ~9 `8 V* ^, \$ ?提示：已知一个圆柱体的顶面温度和侧面、底面温度，求温度分布。/ M6 c* S3 j u
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Title Temperature Distribution in a Short, Solid Cylinder3 r' J. Y W; V6 m( D
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Overview7 _5 k. Y% w$ Y1 b. i" \8 G3 T
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| Reference: | P. J. Schneider, Conduction Heat Transfer, 2nd Printing, Addison-Wesley Publishing Co., Inc., Reading, MA, 1957, pg. 134, fig. 6-7. | | Analysis Type(s): | Thermal Analysis |
( |! s& Z: a& f$ `/ aTest Case
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6 q v' W8 ?# r* L; UA short, solid cylinder is subjected to the surface temperatures shown. Determine the temperature distribution within the cylinder* e/ i8 @) k* i5 g3 p7 b' _- q
4 N4 Z& |# f ?2 c' yFigure 96.1 Short, Solid Cylinder Problem Sketch* \+ Q- @, c$ Y' {; r/ F
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| Material Properties | | k = 1.0 Btu/hr-ft-°F |
| | Geometric Properties | | r =l= 0.5 ft |
| | Loading | | Ttop = 40°F | | Tbot = Twall = 0°F |
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Analysis Assumptions and Modeling NotesSince the problem is axisymmetric, the entire cylinder geometry is not required. An angle Θ = 45° is arbitrarily chosen. Postprocessing is used to print temperatures at the centerline in geometric order. A finer mesh density (than required for reasonable results) is used to produce a smooth isosurface plot.1 k- ~& w1 x% W5 c( B
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Results Comparison| At Centerline | Target | ANSYS | Ratio | | z = 0.0 ft | T, °F | 0.0 | 0.0 | -- | | z = 0.125 ft | T, °F | 6.8 | 6.8 | 1.007 | | z = 0.25 ft | T, °F | 15.6 | 15.4 | 0.984 | | z = 0.375 ft | T, °F | 26.8 | 26.6 | 0.991 | | z = 0.5 ft | T, °F | 40.0 | 40.0 | 1.00 |
1 ?* Y8 Z4 i% B! VFigure 96.2 Temperature Isosurface Display with Annotation! ]* ~* B$ [3 e9 D j
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" Q0 }' ?# H, h/ l7 n" F# i[ 本帖最后由 tigerdak 于 2007-11-6 12:02 编辑 ] |
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发表于 2007-11-6 11:58:30