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发表于 2013-6-14 15:41:56
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来自： 中国广东广州
本帖最后由 topidea 于 2013-6-17 21:00 编辑 5 X4 @; g$ h4 k; g0 w0 B$ N: k
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这还不简单吗? 将 acad.pat 及 acadiso.pat 文件打开，将下边这段加进去
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*钢筋混凝土, Tangent
8 P0 P# z$ H' e45 , 0 ,0,0, 2.5
5 A0 n9 u( }/ a6 |50, 0,0, 4.12975034,-5.89789472, 0.75,-8.25
9 z9 K+ o6 x. _355, 0,0, -2.03781207,7.37236840, 0.60,-6.6
3 C: I: M2 c& c$ }100.4514, 0.5977168,-0.0522934, 5.7305871,-6.9397673, 0.6374019,-7.011421120 K9 N$ C% j! g s7 F, K+ Y
46.1842, 0,2, 6.19462551,-8.84684208, 1.125,-12.3759 U0 ~2 o: ~9 q* C! ~* z& U8 k
96.6356, 0.88936745,1.86206693, 8.59588071,-10.40965104, 0.95610288,-10.51713% m6 f/ H$ C9 f2 f; s2 }, e
351.1842, 0,2, 7.74328189,11.0585526, 0.9,-9.9
2 V# L+ p: P, I, W21, 1,1.5, 4.12975034,-5.89789472, 0.75,-8.25" ^& ^' m3 E6 S% K! P9 u0 z1 B
326, 1,1.5, -2.03781207,7.37236840, 0.60,-6.6) y4 W, l/ I( @; d z0 C0 p# c% q, r
71.4514, 1.49742233,1.16448394, 5.7305871,-6.9397673, 0.6374019,-7.01142112
- m" G! ~) }* @; v r2 B37.5, 0,0, 2.123,2.567, 0,-6.52,0,-6.7,0,-6.625
6 S) \, W+ z1 f/ R9 Z9 ~* a8 c7.5, 0,0, 3.123,3.567, 0,-3.82,0,-6.37,0,-2.5250 o9 v/ ^/ ^5 @. s4 {
-32.5, -2.23,0, 4.6234,2.678, 0,-2.5,0,-7.8,0,-10.35
# \7 | b* K% O-42.5, -3.23,0, 3.6234,4.678, 0,-3.25,0,-5.18,0,-7.35; a) l1 `" \ o* q+ S# R
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