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楼主 |
发表于 2016-3-11 15:51:37
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来自: 中国浙江嘉兴
' Z. W2 ~8 D9 d G9 g" @, l至于用宏的方法,那里可以找到相关资料? 之前已分享不少了,若是不能吸收理解,就僅能抄襲無法廣用.
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如下參考, S. Z; ?- n! {0 Y$ B, \* N
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' ****************************************************************************** {7 c: \0 @9 H" l# ]5 c
' macro recorded on 03/04/16 by scliang
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W: ^4 m: `, n% x. P0 R$ e- z1 ZDim swApp As Object
5 @" K+ I& S/ B* |5 Z2 v" hDim Part As Object, o, r9 y$ O- a/ D" Q [
Dim boolstatus As Boolean
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Sub main()% r% K* d( q& _
Set swApp = Application.SldWorks
3 f$ m7 @+ {# }9 E9 KSet Part = swApp.ActiveDoc
2 W. w/ g9 P/ G5 A) E8 s* d3 gSet myModelView = Part.ActiveView5 o4 O4 |" @* P% g6 y0 C1 `
Dim myDimension As Object* V' R8 E% k# k+ o+ [/ y
pi = Atn(1) * 4
( g% A0 @/ y" ?/ b6 G1 qSet myDimension = Part.Parameter("D15@草圖1") '對應控制角度
/ {, Z- J% E3 ^) K9 f$ oFor i = 0.1 To 90.1 Step 59 v9 @0 g u5 {) T/ `7 M! b( S9 M
A = i * pi / 180
. Z& d$ i& ?+ c# p- x! H" w: @myDimension.SystemValue = A
3 l" l7 M! b! z3 k2 C9 [2 d$ W# w: Oboolstatus = Part.EditRebuild3()+ @) R6 d- C# W- V( g2 L) k
myModelView.RotateAboutCenter 0, 0
+ ?% S( k( f4 v! jNext
% x8 f, Q3 t( i1 s- LFor i = 85.1 To 0.05 Step -5
4 ~5 P+ F3 z [% _- `# o% ]! h" IA = i * pi / 180( u: `/ B* \- D1 c5 z
myDimension.SystemValue = A
/ x6 L3 x7 X: ^0 L- T, P0 d, eboolstatus = Part.EditRebuild3()
$ s0 a0 ?# b: d7 u* N+ pmyModelView.RotateAboutCenter 0, 08 |) s6 H. S3 h8 ]
Next% l9 O s1 k8 ^' v) W
End Sub
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Macro1.rar
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