L1=2500 4 y" c. z+ O. jL2=704.38: i" \6 G. l6 Q' \
L3=2096 0 H [+ Z" a3 [; jL4=577/ u0 R) K) F9 R1 `3 {
AM=3050.7 * G3 a" ]7 N! }1 }THETA1=165*t-751 l" E' a2 t/ I, ^
A=2*L2*L1*SIN(THETA1), Z' Y5 o3 I. b. @/ `+ f( c
B=2*L2*(L1*COS(THETA1)-L4), o" b' T+ l: V. N0 Y4 m2 A$ E8 `4 D
C=L3^2-L1^2-L2^2-L4^2+2*L1*L4*COS(THETA1)' `) n0 l; K' n _; g H0 [3 S
THETA2=2*ATAN((A+SQRT(A^2+B^2-C^2))/(B-C))2 C g3 w* b! x% N' p
/* WARNG: 在函数计算中可能存在错误。: G: r& O% r0 x5 n% B$ j
发表于 2008-12-11 14:26:24
楼主