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本帖最后由 yit02yit02 于 2010-12-10 05:15 编辑 ) E o# T. k' t1 h
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到台灣三重湯城欣昊((充電))上課五天
) d: b7 @! o' ^# k3 V6 u5 x這次幫我們上課的是陳漢傑老師
! `8 p! G' Z: o3 i Q% }' V+ R+ a我也問了關於G82 P10000 萬分位的問題(一般是千分位)
3 ?+ Q% h5 V ^" y( I5 d0 H陳老師也幫我解決了這方面的困擾. e% A/ X4 f+ G' ^- g- k
首先開啟POST
2 C9 V a- X/ y4 @3 K找到
9 d1 T) i. ]9 d! m# h# Format statements - n=nonmodal, l=leading, t=trailing, i=inc, d=delta
" T/ `1 K+ t' X8 ]: c/ \# --------------------------------------------------------------------------, S0 L/ O- ?' I' ?
#Default english/metric position format statements3 A n$ w& a: l6 t; X: w; s( a
fs2 1 0.7 0.6 #Decimal, absolute, 7 place, default for initialize ( " @ z! }* `! m a4 U) Z/ N$ A( G
fs2 2 0.4 0.3 #Decimal, absolute, 4/3 place
' c1 B' N) O0 L6 U4 ~3 g0 Kfs2 3 0.4 0.3d #Decimal, delta, 4/3 place F% s+ a. x0 a! [: C7 t6 a
#Common format statements
' _. @8 |- g, q0 b+ n qfs2 4 1 0 1 0 #Integer, not leading
~' z# \* l# H q. E( n' Ifs2 5 2 0 2 0l #Integer, force two leading
% I2 ^; I" v3 _& rfs2 6 3 0 3 0l #Integer, force three leading
0 {* M+ H" K: Q8 Ifs2 7 4 0 4 0l #Integer, force four leading
0 [& X6 N) J! m- _fs2 8 5 0 5 0l #Integer, force five leading5 C) y1 J. q. y0 i
fs2 9 0.1 0.1 #Decimal, absolute, 1 place
& s7 G: b. x5 m$ hfs2 10 0.2 0.2 #Decimal, absolute, 2 place/ H( o& }- i+ B" K& U$ t2 {5 o
fs2 11 0.3 0.3 #Decimal, absolute, 3 place
: V8 P7 [/ g; b' v. i# K2 ofs2 12 0.4 0.4 #Decimal, absolute, 4 place( o" c L9 E- L i" k7 D6 G) b X+ X4 M
fs2 13 0.5 0.5 #Decimal, absolute, 5 place
$ |3 V7 k k$ V+ C$ g" [/ [fs2 14 0.3 0.3d #Decimal, delta, 3 place
! s# C' X4 r3 W/ y( Z- tfs2 15 0.2 0.1 #Decimal, absolute, 2/1 place (feedrate)
" M6 Q/ y: @, ` B2 e/ E/ Afs2 16 1 0 1 0n #Integer, forced output
" i, ]" [) m" i% j* tfs2 17 1.4 1.3lt #Decimal, absolute, 4/3 trailing
% o/ t& x! h9 [* I" ~" @3 efs2 18 0 4 0 4t (增加這一行)$ `0 F; w' {: d' Z- I
$ |. X! l W+ t8 L, K+ B再找到
- ~5 ]$ S0 e7 G- E# --------------------------------------------------------------------------* v8 g9 o$ A( T1 X+ |% g
fmt N 4 n$ #Sequence number- k, Y$ U* A2 H$ R9 p" y1 w
fmt X 2 xabs #X position output
N; r: r' q; f# c* A c1 cfmt Y 2 yabs #Y position output
0 q9 F6 b8 Z% C* {5 f: Jfmt Z 2 zabs #Z position output S6 M: f: u* `- Y% W$ \4 C) ~6 l4 R
fmt X 3 xinc #X position output# N2 f& e: N: [4 T$ g5 K; R3 g k
fmt Y 3 yinc #Y position output
$ o8 ]2 p% f0 qfmt Z 3 zinc #Z position output
( o+ w( y2 D! y. t, `6 ufmt A 11 cabs #C axis position
+ `0 T$ |. W7 w, U) p; I6 ~0 ^fmt A 14 cinc #C axis position' D1 A/ T% Y; p6 g- r- s& _
fmt A 14 cout_i #C axis position: Y. k! p. O( t0 s$ A
fmt A 4 indx_out #Index position
3 ?: ]3 U5 N2 bfmt R 14 rt_cinc #C axis position, G687 D8 u3 L2 @' |! p- ~2 r0 l6 t
fmt I 3 iout #Arc center description in X2 ]. { `; G3 {3 Y& @6 f
fmt J 3 jout #Arc center description in Y8 u8 F0 L- A+ N( l" W5 N0 I8 ]; }
fmt K 3 kout #Arc center description in Z1 |% a! v( W( s* P8 G
fmt K 2 lead #Helical lead
" k3 z/ l" F G, Q0 a/ \" U0 J4 @8 l6 Qfmt R 2 arcrad$ #Arc Radius1 Q! T( V8 {/ j/ S9 d1 {8 b# {
fmt F 15 feed #Feedrate
( s* I T1 L& w. W+ M8 \. @fmt P 11 dwell$ #Dwell (把P11改P18)
9 U4 s& ^( ~5 L* j( a. q4 Pfmt M 5 cantext$ #Canned text
$ v. Z5 `# U1 T! zfmt 4 mr2$ #HSM
9 H+ f- [; u4 M7 d$ H9 U程式選G82時暫停時間打1.0
' S9 ]8 K3 c7 _5 m0 e轉出來就會是G82 P10000
! J& |8 D/ I2 M% W" u8 R真是謝謝)))陳老師))))) |
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发表于 2010-12-10 05:08:54
楼主