ug表达式问题希望高手回答

李林杰

$ x+ N) Z% _1 F" T* Z! q3 i( [
x=(128*sin(180/18 + atan((16*cos(180/18) - 15)/(16*sin(180/18))))*((16*cos(180/18) - 15)^2/(256*sin(180/18)^2) + 1)^(1/2)*(sin(180/18)*sin(k)^2 + cos(180/18)*sin(180/18)*cos(k)*(cos(k) - 1)))/3 + (128*cos(180/18 + atan((16*cos(180/18) - 15)/(16*sin(180/18))))*((16*cos(180/18) - 15)^2/(256*sin(180/18)^2) + 1)^(1/2)*(cos(k)*(cos(k) - sin(180/18)^2*cos(k)^2*(cos(k) - 1)) + sin(k)*(cos(180/18)*sin(k) - sin(180/18)^2*cos(k)*sin(k)*(cos(k) - 1))))/3
+ c- J5 j6 ~. l, sy=- (128*sin(180/18 + atan((16*cos(180/18) - 15)/(16*sin(180/18))))*(sin(180/18)*cos(k)*sin(k) - cos(180/18)*sin(180/18)*sin(k)*(cos(k) - 1))*((16*cos(180/18) - 15)^2/(256*sin(180/18)^2) + 1)^(1/2))/3 - (128*cos(180/18 + atan((16*cos(180/18) - 15)/(16*sin(180/18))))*((16*cos(180/18) - 15)^2/(256*sin(180/18)^2) + 1)^(1/2)*(cos(k)*(cos(k)*sin(k)*(cos(k) - 1)*sin(180/18)^2 + cos(180/18)*sin(k)) - sin(k)*(cos(k) - sin(180/18)^2*sin(k)^2*(cos(k) - 1))))/3
4 X! w' C2 a4 E+ o  |z=(128*cos(180/18 + atan((16*cos(180/18) - 15)/(16*sin(180/18))))*((16*cos(180/18) - 15)^2/(256*sin(180/18)^2) + 1)^(1/2)*(cos(k)*(sin(180/18)*sin(k)^2 - cos(180/18)*sin(180/18)*cos(k)*(cos(k) - 1)) - sin(k)*(sin(180/18)*cos(k)*sin(k) + cos(180/18)*sin(180/18)*sin(k)*(cos(k) - 1))))/3 - (128*sin(180/18 + atan((16*cos(180/18) - 15)/(16*sin(180/18))))*(cos(k) - cos(180/18)^2*(cos(k) - 1))*((16*cos(180/18) - 15)^2/(256*sin(180/18)^2) + 1)^(1/2))/3
这个方程在ug当中画出曲线
k是变量 从0到360度
% Z# {1 ^1 T( T6 r希望高人解答

WHC44

# w: z1 Q3 _" N4 B3 M: n. }* N' b2 J首先变量由k变为t，因为UG的默认变量为t，范围0～1；其二，要把方程式中的函数转为UG能识别的函数，如式中atan要变为arctan。不过，可能是公式复杂，UG报警。

李林杰

2# WHC44
我按照你说的做了 可是不好用是不是ug本身的计算有问题？？

luo3064

按UG的规则来，不会出错，我生成过一次凸轮，也费了很大的劲才搞起的。

李林杰

我把式子化简成这样
; P6 z8 X- [/ F3 D: Ux=(128*sin(10 + arctan((16*cos(10) - 15)/(16*sin(10))))*((16*cos(10) - 15)^2/(256*sin(10)^2) + 1)^(1/2)*(sin(10)*sin(360*t)^2 + cos(10)*sin(10)*cos(360*t)*(cos(360*t) - 1)))/3 + (128*cos(10 + arctan((16*cos(10) - 15)/(16*sin(10))))*((16*cos(10) - 15)^2/(256*sin(10)^2) + 1)^(1/2)*(cos(360*t)*(cos(360*t) - sin(10)^2*cos(360*t)^2*(cos(360*t) - 1)) + sin(360*t)*(cos(10)*sin(360*t) - sin(10)^2*cos(360*t)*sin(360*t)*(cos(360*t) - 1))))/3
% o, f9 }' V6 N( B1 W# ^0 N9 }y=- (128*sin(10 + arctan((16*cos(10) - 15)/(16*sin(10))))*(sin(10)*cos(360*t)*sin(360*t) - cos(10)*sin(10)*sin(360*t)*(cos(360*t) - 1))*((16*cos(10) - 15)^2/(256*sin(10)^2) + 1)^(1/2))/3 - (128*cos(10 + arctan((16*cos(10) - 15)/(16*sin(10))))*((16*cos(10) - 15)^2/(256*sin(10)^2) + 1)^(1/2)*(cos(360*t)*(cos(360*t)*sin(360*t)*(cos(360*t) - 1)*sin(10)^2 + cos(10)*sin(360*t)) - sin(360*t)*(cos(360*t) - sin(10)^2*sin(360*t)^2*(cos(360*t) - 1))))/3
* P, q( Y( }6 Y& Y: cz=(128*cos(10 + arctan((16*cos(10) - 15)/(16*sin(10))))*((16*cos(10) - 15)^2/(256*sin(10)^2) + 1)^(1/2)*(cos(360*t)*(sin(10)*sin(360*t)^2 - cos(10)*sin(10)*cos(360*t)*(cos(360*t) - 1)) - sin(360*t)*(sin(10)*cos(360*t)*sin(360*t) + cos(10)*sin(10)*sin(360*t)*(cos(360*t) - 1))))/3 - (128*sin(10 + arctan((16*cos(10) - 15)/(16*sin(10))))*(cos(360*t) - cos(10)^2*(cos(360*t) - 1))*((16*cos(10) - 15)^2/(256*sin(10)^2) + 1)^(1/2))/3
还是不好用

lhj7103

UG在输入表达式时要先定义变量t

李林杰

6# lhj7103
# A1 q. E8 v) S+ [' B变量t已经定义了