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UID396100
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注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器
0 e# s9 K5 S1 C 插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗
3 [$ w1 R# p: P( QSub jkx()0 y3 a# V8 j6 u* g9 b5 r7 p
Rem 绘制渐开线,
2 m! W" n/ I5 _% M; v* fDim d As Double '节圆直径
- }0 `/ `& [% `4 MDim r As Double '节圆半径
7 [' o' f3 U' Q/ O: q7 `( sDim A As Double '总展开角度! E$ z$ m1 \- s# l% _
Dim Ai As Double '展开角度$ K& V& D+ `+ u
Dim Li As Double '展开弧长
6 }8 ~' V! h8 V0 j' Sd = 100! d: q! x: L3 V' v9 H/ Q3 v
A = 360" a" l6 ~& H" o3 U e4 h
r = d / 24 W( D& h7 n! o% @( Q" Y$ _& T5 a
Dim Pnt1(2) As Double" J$ G8 h5 @9 L7 l- T: Q- p2 s9 i1 _$ w
Dim Pnt2(2) As Double
4 W L2 t3 t. Y. f: a2 D, r- _Dim PntLst() As Double, N As Integer6 Y, @( e9 v( ^# q& @! k) q
ThisDrawing.ModelSpace.AddCircle Pnt1, r2 X5 ~+ r8 Y# E& H7 ?1 b
For Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45## @7 Q3 m5 M7 m* T
Li = r * Ai! S) j" U {7 ? t$ q
Pnt1(0) = r * Sin(Ai)6 v2 Q8 b# X9 {. B0 m
Pnt1(1) = r * Cos(Ai)
: _1 M7 y: u! G, PPnt2(0) = Pnt1(0) - Li * Cos(-Ai)$ [% m/ y5 Y" W# Q1 R5 M
Pnt2(1) = Pnt1(1) - Li * Sin(-Ai)
7 \; i$ l: r3 C4 ?ThisDrawing.ModelSpace.AddLine Pnt1, Pnt2
" P4 z( G' a7 k" m1 Q3 IN = N + 1
/ E& C) y" R1 {ReDim Preserve PntLst(N * 2 - 1)
6 {: t9 ]4 v8 i, v7 n( ^ @PntLst(N * 2 - 2) = Pnt2(0)
' M4 g% a3 l$ y1 m( I( t- oPntLst(N * 2 - 1) = Pnt2(1)
: e+ u" [7 [& O) [ Q8 D, mNext
7 j( ]- Q* R! Z( E0 Q! i N' f* I# tIf N > 1 Then
0 Z, K5 H! c& VThisDrawing.ModelSpace.AddLightWeightPolyline PntLst
! j# p8 G" z4 k) ~End If8 a1 q2 u( G& R$ ?" X6 f
End Sub |
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