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发表于 2007-1-12 09:22:11
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来自: 中国辽宁营口
autocad的功能极其强大,使用基本画图命令、计算、编程都是可选的做图方法。“条条大路通罗马”,用最简洁的途径,得到最准确的结果,才能称得上是技巧。限制使用某些基本做图命令而不去尝试autocad其它更强大的功能,窃以为不妥。试问:谁能用画圆的命令生成一条直线?: s' I1 i$ V( z j1 f
以下是用VBA求解的过程。& b$ {5 F- k2 \
附:源代码
程序加载和做图过程
程序注释用图
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Sub NT()0 o- B" V- k2 b9 g& r4 r0 L) B* H% y
On Error GoTo 10 '发生错误时退出程序
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Dim A As Variant 'A点坐标+ _7 f2 v2 p+ l, c
Dim C As Variant 'C点坐标! q( }9 P: [& O" W" }, L; m
Dim B(2) As Double 'B点坐标; u$ {( i' |( }) D3 J. {, H+ }
Dim P1 As Variant '直线12起点坐标
0 a" ^) @* f1 r( B) K, ], _ Dim P2(2) As Double '直线12端点坐标
% c4 g* p- w, b7 {& s# [ O% S Dim R As Double '圆Y半径
; R+ J- ~: v0 K2 ~5 Q: D3 J Dim LineAC As AcadLine '直线AC7 p. q& `7 S# W- P/ {' f. d
Dim Y As AcadCircle '圆Y
% }# Y& q2 W. i, r Dim OC As Double 'C点到直线AB中点的高
3 r8 J3 ~1 [) \) c5 J: m# a0 C' S Dim AB As Double '直线AB长度
5 K9 w+ u3 {$ x p5 f( ^ Dim M1 As Double '迭代运算左边界点的横坐标& S/ C6 ?. a6 g: r
Dim M2 As Double '迭代运算右边界点的横坐标5 A- a' K- r! e
Dim Yc(2) As Double '题目中拉伸点的坐标
+ i; y. K$ ]% A. m' p Dim X As Double '圆Y与直线AB交点的横坐标
# s/ Z0 `5 @$ Y! d- A4 i5 d/ c. O Dim X2 As Double '圆Y与直线AB交点的横坐标* c3 l2 W/ ]1 p3 Y+ O! m: m' [
Dim S As Long '曲线拟合点数量(3~32767)5 I7 l. f+ X* n! Q7 V
Dim K() As Double '拟合点坐标# D' ` g8 S7 P% ~8 ?
Dim St(2) As Double '曲线起点切向
# Y9 b/ x( Y g; c! d- s8 _5 u Dim Et(2) As Double '曲线端点切向
% b# [2 F8 n4 F' J2 }7 U5 { Dim I As Long '循环变量6 t; I4 ?9 y+ P! S
. i, X" u6 q: a8 ? With ThisDrawing5 n9 c( A5 B7 V
A = .Utility.GetPoint(, vbCrLf & "指定A点位置:") '指定A点位置
+ u3 Y" L5 y! f3 L% } Do '指定C点位置,当用户给出的位置不在规定范围时重新要求指定位置。
3 J$ y# o' H* t* Y C = .Utility.GetPoint(A, vbCrLf & "指定C点位置(在A点右上方):")
! Q! o% l0 w) ~ If C(0) > A(0) And C(1) > A(1) Then Exit Do" ^) Z2 t+ A& j& J
Loop
2 u5 o' b" f- O) Q+ w7 k OC = C(1) - A(1) '计算B点坐标3 ~ k: y% T1 F4 D9 {9 H# e
AB = 2# * (C(0) - A(0))
% [* m: `% r j; v Q) R B(0) = A(0) + AB
( f1 C1 s3 {6 e% A2 }+ P B(1) = A(1)
+ o c6 e- V# c Set LineAC = .ModelSpace.AddLine(A, C) '画AC直线9 ~" ?6 Z% M2 t
.ModelSpace.AddLine A, B '画AB直线
# Z9 Y6 r! E, a .ModelSpace.AddLine B, C '画BC直线& P. V4 O3 u5 u
Do '指定圆Y半径,当用户给出的半径不在规定范围时重新要求指定半径。; l( N$ E9 ^9 r) |% h6 [- D
R = .Utility.GetDistance(A, vbCrLf & "指定圆的半径(小于AC长度):") W( b: ~* P5 |, p4 f
If R < OC And R > 0 Then Exit Do, W$ M' }7 f2 Z& _4 u4 k# @8 [
Loop
: [4 h3 u- K/ t7 [$ d1 y; D Set Y = .ModelSpace.AddCircle(A, R) '以A点为圆心画圆Y. T7 d; s- a; [4 _% v5 x
P1 = .Utility.GetPoint(, vbCrLf & "指定直线12位置:") '指定直线12上的一个点
( z3 P( F2 Q; Q* v P1(1) = C(1) '计算直线12起端点坐标
9 V" |' N" R1 k* P P2(0) = P1(0)3 K6 s: F% a9 c c3 }
P2(1) = A(1)
0 P) r# M) N3 J1 p2 X) J+ l0 w& V3 y .ModelSpace.AddLine P1, P2 '画直线12
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M1 = P1(0) - R '以直线12左侧R远为迭代运算初始左边界
: o. D' t; E- Q+ C; q M2 = P1(0) + R '以直线12右侧R远为迭代运算初始右边界/ c3 |$ j+ f5 a6 o$ {- k" O- \' V0 i
Yc(1) = A(1) '拉伸点纵坐标与A点相同
' g; @; x' x% m5 ^' N, l6 ?, _ Do '迭代运算 B% y0 d' ^2 Z# g/ b
Yc(0) = (M1 + M2) / 2# '把拉伸点置于两边界中点,计算此时圆Y与AC交点横坐标
: M# g+ V5 c# T X = C(0) + (Yc(0) - C(0)) * (Sqr((Yc(0) - C(0)) ^ 2 + OC ^ 2) - R) / Sqr((Yc(0) - C(0)) ^ 2 + OC ^ 2)
( h" R. T0 d) U" j: d' _+ H$ X If X = P1(0) Then '交点与直线12重合,结束运算4 C- G3 `; ^; Q% Q) V
Exit Do
" z- _' G( o( @ ElseIf Yc(0) = M1 Then '拉伸点与左边界重合,边界已收敛到双精度数据极限,结束迭代运算
2 H9 e7 J" Z e& W! q '以右边界为拉伸点,计算交点,并与左边界为拉伸点时的结果比较,取精度高者为最终结果* u% U' K. V3 K" s3 g8 z# V1 ^1 o$ k
X2 = C(0) + (M2 - C(0)) * (Sqr((M2 - C(0)) ^ 2 + OC ^ 2) - R) / Sqr((M2 - C(0)) ^ 2 + OC ^ 2)
, ~! o! h( D9 d; {1 Q If Abs(X2 - P1(0)) < Abs(X = P1(0)) Then Yc(0) = M26 t5 T. B2 q' d% l, ?5 @
Exit Do
; H* g. K1 ^% p" E# ?' C ElseIf Yc(0) = M2 Then '拉伸点与右边界重合,边界已收敛到双精度数据极限,结束迭代运算& F$ e9 q3 F! t) |- E
'以左边界为拉伸点,计算交点,并与右边界为拉伸点时的结果比较,取精度高者为最终结果
/ B4 A( G0 U* D2 J X2 = C(0) + (M1 - C(0)) * (Sqr((M1 - C(0)) ^ 2 + OC ^ 2) - R) / Sqr((M1 - C(0)) ^ 2 + OC ^ 2)
+ d9 y9 l* }: S If Abs(X2 - P1(0)) < Abs(X = P1(0)) Then Yc(0) = M1
: H. { l2 ?( u6 D/ T' V Exit Do
: Q. u4 E( q3 S+ A ElseIf X < P1(0) Then '试运算的交点在直线12左侧,将左边界收敛到现拉伸点,重新运算 o, T" z3 ~: X! b `2 z" I( ^
M1 = Yc(0)2 `! R5 n) {5 r4 A3 o4 X# ~& N9 Q$ o
Else '试运算的交点在直线12右侧,将右边界收敛到现拉伸点,重新运算. J8 i7 c3 Y" W" p0 ?
M2 = Yc(0)
# p; I9 R7 u/ T* F. w) p6 t+ Q End If
6 G' _ J" C' E8 ^( d Loop
4 l7 y3 P( R' x* k, r$ y LineAC.StartPoint = Yc '按计算结果移动直线AC起点8 ^4 X, D, C% u7 B X
Y.Center = Yc '按计算结果移动圆Y
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! [! k j6 a7 `5 P$ J2 P, c Do ''指定拟合点数量,当用户给出的数量不在规定范围时重新要求指定数量。) b; a( J- `9 ?- m* X
S = .Utility.GetInteger(vbCrLf & "指定曲线拟合点数量(3到32767之间正整数):"). Z" |) G) x7 A2 e
If S > 2 Then Exit Do
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ReDim K(3 * S - 1) '按拟合点数量重新定义数组上界
) H% u. U0 w N; t* B& n For I = 0 To S - 1 '圆Y和直线AC起点以直线AB长度的(S-1)分之一为步长从左向右移动,逐点计算圆Y和直线AC交点,做为拟合点坐标& U1 n, \' _8 {$ N9 I5 O, M5 z
Yc(0) = A(0) + I / (S - 1) * AB
" Z0 u4 r/ s4 M4 P" V K(I * 3) = C(0) + (Yc(0) - C(0)) * (Sqr((Yc(0) - C(0)) ^ 2 + OC ^ 2) - R) / Sqr((Yc(0) - C(0)) ^ 2 + OC ^ 2)
" R4 \$ ]- [) O2 W! S b K(I * 3 + 1) = A(1) + Sqr(R ^ 2 - (K(I * 3) - Yc(0)) ^ 2) S; y2 r: a0 Y2 s+ [9 l
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St(0) = 1 '曲线起点切向: \$ q. z ^5 h3 Q: D! z* |# {
St(1) = Sqr(R ^ 2 - (K(1) - A(1)) ^ 2) / (R ^ 2 / (K(1) - A(1)) + (C(1) - K(1)) * R ^ 2 / (K(1) - A(1)) ^ 2 - (K(1) - A(1)))
- ]( r2 I6 c4 c+ u7 e Et(0) = 1 '曲线端点切向5 q( [: S3 C9 }: T3 }5 y# q
Et(1) = -St(1)
0 F; A: d. e1 A+ Y% Y8 S .ModelSpace.AddSpline K, St, Et '画样条曲线- |8 f4 V0 h# ^' [" V/ w9 T: J, r
End With
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2 x# U) s2 y/ `End Sub
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[ 本帖最后由 woaishuijia 于 2007-1-12 19:24 编辑 ] |
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程序和附图
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